Free PDF 2025 The Best 1Z0-819: Sample Java SE 11 Developer Test Online
Free PDF 2025 The Best 1Z0-819: Sample Java SE 11 Developer Test Online
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Oracle 1Z0-819 (Java SE 11 Developer) Certification Exam is a professional certification exam designed to test the skills and knowledge of Java developers. It is a globally recognized certification that validates the expertise of developers in Java programming language and related technologies.
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Oracle Java SE 11 Developer Sample Questions (Q93-Q98):
NEW QUESTION # 93
Given:
and
Which two method definitions at line n1 in the Bar class compile? (Choose two.)
- A. public List<Number> foo(Set<String> m) {...}
- B. public List<Integer> foo(TreeSet<String> m) {...}
- C. public ArrayList<Number> foo(Set<CharSequence> m) {...}
- D. public ArrayList<Integer> foo(Set<String> m) {...}
- E. public List<Integer> foo(Set<CharSequence> m) {...}
- F. public List<Object> foo(Set<CharSequence> m) {...}
Answer: B,C
NEW QUESTION # 94
Given:
String originalPath = "data\projects\a-project\..\..\another-project"; Path path = Paths.get(originalPath); System.out.print(path.normalize()); What is the result?
- A. data\projects\a-project\..\..\another-project
- B. dataanother-project
- C. dataprojectsa-projectanother-project
- D. dataprojectsa-project....another-project
Answer: D
Explanation:
NEW QUESTION # 95
Given:
What is the output?
- A. appleorangebanana
:APPLE:ORANGE:BANANA - B. :APPLE:ORANGE:BANANA
- C. apple:APPLE orange:ORANGE banana:BANANA
- D. APPLE:apple ORANGE:orange BANANA:banana
- E. :APPLE:ORANGE:BANANA
appleorangebanana
Answer: C
Explanation:
NEW QUESTION # 96
Given the code fragment:
Which two code snippets inserted independently inside println method print Mondial:domainmodel? (Choose two.)
- A. new Main().prefix + new Main().name
- B. prefix + name
- C. Main.prefix + Main.getName()
- D. prefix + Main.name
- E. Main.prefix + Main.name
- F. prefix + getName
Answer: C,F
NEW QUESTION # 97
Given the code fragment:
public void foo(Function<Integer, String> fun) {...}
Which two compile? (Choose two.)
- A. foo( int n -> Integer.toHexString(n) )
- B. foo( n -> n + 1 )
- C. foo( (int n) -> Integer.toHexString(n) )
- D. foo( n -> Integer::toHexString )
- E. foo( n -> Integer.toHexString(n) )
- F. foo( n::toHexString )
- G. foo( toHexString )
- H. foo( Integer::toHexString )
Answer: B,E
Explanation:
Explanation/Reference:
NEW QUESTION # 98
......
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